CHEMITRY

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what is solubility, in mol/L, of MgCO3 in a 0.65 mol/L solution of MgCL2 if the ksp of MgCO3 is 2.5*10^-5

  • CHEMITRY -

    MgCO3 ==> Mg^2+ + CO3^2-
    ....x......x........x
    where x = solubility in mols/L.

    ........MgCl2 --> Mg^2+ + 2Cl^-
    I........0.65.....0..........0
    C.......-0.65....0.65.....2*0.65
    E .......0.........0.65....1.30

    Substitute from the above ICE charts into Ksp for MgCO3 and solve for x.
    (Mg^2+) = x+0.65 (that's x from MgCO3 and 0.65 from MgCl2.)
    (CO3^2-) = x

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