calculus

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1) find the indicated limit, if it exist?

a) lim x->-2 (x^2 -9)/(x^2+x-2)
b) lim x -> -∞ √(ax^2+bx+c)/dx + e, where a > 0, b,c,d, and e are constant.

  • calculus -

    a)
    since you have (x-3)(x+3) / (x-1)(x+2) the numerator is nonzero when x = -2, the limit will be ±∞, depending on the direction of approach,

    b)
    I assume you meant √(ax^2+bx+c)/(dx+e) since otherwise it is boring. Divide top and bottom by x to get
    √(a+b/x+c/x^2)/(d+e/x) = √a/d
    however, the numerator is positive and the denominator is negative as x -> -∞, so we really end up with -√a/d

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