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A chemical system within a sealed 1 L reaction vessel is described by the following reversible reaction equation:

2H2S(g) <---> 2H(g) + S2(g)

(a) the reaction quotient intially
(b) the order of concentration of all three components at equilibrium without using calculations
(c) what the size of the reaction quotient indicates regarding the extent of the forward reaction
(d) the quilibrium concentration of sulphur gas if 0.070 mol of hydrogen sulphide gas is intially placed in the vessel

Any help would be appreciated :)

  • Chemistry -

    I think you made a typo. I think you meant
    2H2S(g) ==> 2H2(g) + S2(g)

    a. Qrxn = (H2)^2(S)/(H2S)^2
    ASSUMING H2S was placed in the vessel then Qrxn = 0 since 0/any number = 0
    b. I know Keq must be very small. At equilibrium, from lowest to highest concn S2, then H2, then H2S.
    c. 0 means the forward reaction is minimal.
    d. Can't be solved without knowing Kp or Kc.

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