# Calculus AB

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I'm trying to find the second derivative of h(x)= x^2 + cos(kx)

My answer for h'(x) is 2x - ksin(kx) but I'm not sure if that's right.

Then the answer I got for h''(x) was h''(x) = 2 - k^2cos(kx) but I'm pretty sure that's wrong based on the graph I was given.

Is my answer for the first derivative right? Thanks!

• Calculus AB -

Oh nevermind, something was just set weird on my calculator that was throwing the graph off. I reset it and it looked like it was supposed to.

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