Chemisty

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A 0.5-L saturated solution of silver chloride, AgCl, is evaporated to dryness. The residue is equivalent to 1.4 x 10^-3 mole. Calculate the experimental value of the Ksp of silver chloride. Show all of your work.

  • Chemisty -

    ....AgCl ==> Ag^+ + Cl^-
    ......x.......x......x
    mols AgCl = 1.4E-3 mols in 1/2 L; therefore, you will have 1.4E-3 mol x 2 = 2.8E-3 mols in a L.
    Ksp = (Ag^+)(Cl^-)
    Ag^+ = Cl^- = 2.8E-6
    Substitute and solve for Ksp. Not good experimental result.

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