Post a New Question

CALCULUS

posted by .

The region R is a rectangle with vertices P(a,lna), Q(a,0), S(3,0), and T(3,lna), where 1<a<3.
I found that the expression for the area of the rectangle is f(a) = (ln(a))(3-a).
The area of the rectangle is maximized for some c beween 1 and 3. Write the expression you would need to solve in order to find c.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question