how to Calculate the molarity of a solution if sulphuric acid contains 13%H2SO4 by mass and density is 1.02 gm per cm3.

mass of 1000 cc =

1.02 g/cc x 1000 cc = ? grams.
Is all of the H2SO4? NO, only 13% is H2SO4. So how much H2SO4 do you have?

mass H2SO4 = ?grams soln x 0.13 = xx g H2SO4.

How many mols is that? mols = g/molar mass
mols H2SO4 = xxgrams H2SO4/molar mass H2SO4 = ?
So now you have mols H2SO4/1000 cc soln and that is M.

To calculate the molarity of a solution, we need to know the mass percentage of the solute (H2SO4), the density of the solution, and the molar mass of the solute. Here's how you can calculate the molarity:

1. Determine the molar mass of H2SO4:
- Hydrogen (H) atomic mass = 1 g/mol
- Sulfur (S) atomic mass = 32.07 g/mol
- Oxygen (O) atomic mass = 16 g/mol
- Multiply the atomic masses by their respective subscripts and sum them up to calculate the molar mass of H2SO4:
Molar mass of H2SO4 = (2 * 1) + 32.07 + (4 * 16) = 98.09 g/mol

2. Calculate the mass of H2SO4 in the solution:
- If the solution contains 13% H2SO4 by mass, it means that 100 g of the solution contains 13 g of H2SO4.
- Therefore, in the solution, the mass of H2SO4 is 13% of the total mass of the solution.

3. Determine the volume of the solution:
- Density is given as 1.02 g/cm3, which means that 1 cm3 of the solution has a mass of 1.02 g.
- Use the mass of the solution and its density to calculate the volume of the solution using the formula:
Volume (in cm3) = Mass (in g) / Density (in g/cm3)
Convert the volume to liters by dividing it by 1000.

4. Calculate the molarity of the solution:
- Molarity (M) is defined as the moles of solute per liter of the solution.
- Moles of solute = Mass of solute (in g) / Molar mass of solute (in g/mol)
- Convert the volume of the solution from cm3 to liters.
- Molarity (M) = Moles of solute / Volume of solution (in liters)

By following these steps, you can calculate the molarity of the solution of sulfuric acid.