A ball is dropped from a tall building
What is its acceleration
What does the acceleration tell us about the velocity of the ball
i believe its was 9.8 mph persec
by gravity its going to far at a rate of 9.8 per sec you can drop basicly anything down a building and it will still fall the same speed. well basicly gravity
acceleration is 9.8 m/s^2 (!),
Acceleration shows how the speed changed during the 1 second of accelerated motion
To determine the acceleration of the ball when it is dropped from a tall building, you can use the formula for acceleration:
acceleration (a) = change in velocity (Δv) / change in time (Δt)
When the ball is dropped, it starts from rest (initial velocity, vi = 0 m/s). As it falls, its velocity increases. Assuming there is negligible air resistance, the acceleration due to gravity (g) is constant and equal to 9.8 m/s². We can take this as the value for acceleration since the ball is only affected by gravity during its free fall.
Therefore, the acceleration of the ball when it is dropped is approximately 9.8 m/s² (downward).
Acceleration tells us about the rate at which velocity changes. In this case, since the acceleration is constant, we can infer that the velocity of the ball increases at a steady rate of 9.8 m/s². This means that for each second the ball falls, its velocity increases by 9.8 m/s. The direction of the acceleration (downward) indicates that the velocity is increasing in the downward direction.