KMno4+NaHso3
How to balance redox equations.
http://www.chemteam.info/Redox/Redox.html
KMnO4 (potassium permanganate) and NaHSO3 (sodium bisulfite) are two chemical compounds. When combined, they can undergo a redox reaction.
To understand what happens when KMnO4 reacts with NaHSO3, we need to balance the equation. Let's start by writing the unbalanced equation:
KMnO4 + NaHSO3 -> ?
To balance the equation, we need to consider the oxidation states of each element. In KMnO4, the oxidation state of Mn is +7, and in NaHSO3, the oxidation state of S is +4.
In the reaction, the Mn in KMnO4 is reduced from +7 to +2, while the S in NaHSO3 is oxidized from +4 to +6. To balance the equation, we need to make sure the total charge on both sides is equal.
The balanced equation is:
2 KMnO4 + 3 NaHSO3 -> K2SO4 + 2 MnSO4 + 3 H2O + 2 CO2 + NaOH
As a result, the products of the reaction are potassium sulfate (K2SO4), manganese(II) sulfate (MnSO4), water (H2O), carbon dioxide (CO2), and sodium hydroxide (NaOH).
It's important to note that during this redox reaction, the permanganate ion (MnO4-) acts as an oxidizing agent and the bisulfite ion (HSO3-) acts as a reducing agent. These reactions can be useful in various chemical applications, such as in the laboratory or industrial settings.