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posted by Jennifer .
The 9th term of an Arithmetic Progression is 8 and the 4th term is 20. Find the first term and the common difference.

There are 5 terms, with a total difference of 12, so d = 12/5
a + 3(12/5) = 20
a  36/5 = 20
a = 136/5
So, the sequence is
136/5, 124/5, 112/5, 100/5=20, 88/5, 76/5, 64/5, 52/5, 40/5=8, ... 
The sum of the 6 and 8 term of an ap is 142,if the 4 term is 49 calculate the first term
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