Application problems and converting decimals is not my forte. Please help me?
mows the lawn in 7 hrs. Mary can do the same yard in 6 hrs. How much time would it take for them to mow the lawn together? (They are sober btw)
8.26 x 10^7 Convert to decimal notation please.
I keep messing up on the 0's
An explanation could be helpful.
Thanks
the 10^7 means you move the decimal 7 places to the right
so 8.26 would be 82600000. those wouldnt be o's though i just don't know hwat the number is
(a)
x/7 + x/6 =13•x/42,
x /(13•x/42) = 42/13 =3.23 Hrs.
(b) 8.26 x 10^7 = 82,600,000
Of course, I'd be happy to help you with these problems!
First, let's tackle the problem of working together to mow the lawn. To solve this type of problem, we can use the concept of rates. 's rate of mowing the lawn is 1 yard per 7 hours, and Mary's rate is 1 yard per 6 hours.
To find the combined rate when they work together, we add up their individual rates. So and Mary together can mow 1 yard per (1/7 + 1/6) hour. We can simplify this expression by finding a common denominator, which is 42.
So the combined rate for and Mary is 1 yard per (6/42 + 7/42) hour, which simplifies to 1 yard per 13/42 hour. To convert this to decimal notation, we divide 1 by (13/42).
Dividing 1 by (13/42) gives us approximately 3.2308 (rounded to four decimal places). Therefore, it would take and Mary approximately 3.2308 hours to mow the lawn together.
Now let's move on to converting the given number to decimal notation.
When we have a number in scientific notation like 8.26 x 10^7, we can convert it to decimal notation by moving the decimal point to the right or left according to the exponent value.
In this case, the exponent is positive, indicating that we need to move the decimal point to the right. The exponent 7 tells us to move the decimal point 7 places to the right. Starting from 8.26, we move the decimal point 7 places to the right, which gives us the decimal notation of 82,600,000.
So, 8.26 x 10^7 is equivalent to 82,600,000 in decimal notation.
I hope this explanation helps you understand how to approach these problems. If you have any further questions, feel free to ask!