posted by Randy .
calculate the molarity of an acetic acid solution if 83.71 mL of the solutions needed to neutralize103 mL of 1.08 M sodium hydroxide. the equation for the reaction is. HC2H3O2(aq) + NaOH(aq) >Na+(aq) + C2H3)2(aq) +H2O(aq) Please show your work i really don't understand what it is they want.
M acid x mL acid = M base x mL base