6% of american drivers read the newspaper while driving if 300 drivers are selected at random find the probability that between 15 and 25 say they read while driving

Mean = np = 300 * .06 = ?

Standard deviation = √npq = √(300 * .06 * .94) = ? (Note: q = 1 - p)

Once you have calculated mean and standard deviation, use z-scores to find the probability.

z = (x - mean)/sd

Find two z-scores, using 15 for x and then using 25 for x.

Once you find the z-scores, use a z-table to find the probability between the two scores.

I hope this will help get you started.

To solve this problem, we need to use the binomial probability formula. The binomial probability formula is given by:

P(X = k) = (n C k) * p^k * (1-p)^(n-k)

Where:
P(X = k) is the probability of getting exactly k successes in n trials.
n is the total number of trials or drivers selected.
k is the number of successes or drivers who claim to read while driving.
p is the probability of success (in this case, the likelihood of a driver reading while driving).

In our case:
n = 300 (the number of drivers selected)
k ranges from 15 to 25 (the number of drivers who claim to read while driving)
p = 0.06 (6% of American drivers read the newspaper while driving)

Now, we can calculate the probability for each value of k (from 15 to 25) and then sum them up to find the total probability.

P(15 ≤ X ≤ 25) = P(X = 15) + P(X = 16) + ... + P(X = 25)

Let's calculate the probability for each value of k:

P(X = 15) = (300 C 15) * (0.06^15) * (0.94^285)
P(X = 16) = (300 C 16) * (0.06^16) * (0.94^284)
...
P(X = 25) = (300 C 25) * (0.06^25) * (0.94^275)

After calculating the probability for each value of k, we can sum them up to find the total probability between 15 and 25 drivers claiming to read while driving.