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Solve the following system using substitution. Write the solution as an ordered pair, (a, b).

b = a – 4
2a – 3b = -2

  • math -

    okay just equation 1 has b= a - 4 we can plug in a- 4 for b in equation 2 to give you;

    2a - 3(a - 4) = -2

    2a - 3a +4= -2

    -a + 4 = -2

    -a = -6

    divide by negative 1 to make a postive
    a= 6 now you can plug in 6 into either equation to solve for b

    but i would use equation 1 since its so short b = 6- 4 , b= 2

    (6, 2)

  • math -

    i hope that helps if your confuse about anything with the above solution just ask and ill try to clarify

  • math -

    The only problem is, a=6 b=2 does not satisfy the original equations.

    If you work it more carefully, you will wind up with

    a=14
    b=10

    hint: -3(a-4) is not -3a+4

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