math
posted by Jorge .
Solve the following system using substitution. Write the solution as an ordered pair, (a, b).
b = a – 4
2a – 3b = 2

okay just equation 1 has b= a  4 we can plug in a 4 for b in equation 2 to give you;
2a  3(a  4) = 2
2a  3a +4= 2
a + 4 = 2
a = 6
divide by negative 1 to make a postive
a= 6 now you can plug in 6 into either equation to solve for b
but i would use equation 1 since its so short b = 6 4 , b= 2
(6, 2) 
i hope that helps if your confuse about anything with the above solution just ask and ill try to clarify

The only problem is, a=6 b=2 does not satisfy the original equations.
If you work it more carefully, you will wind up with
a=14
b=10
hint: 3(a4) is not 3a+4