# Pre-Calc/Math

posted by .

Prove the identit: cosxcotx+sinx=cscx

• Pre-Calc/Math -

1) rewrite cosx (cosx/sinx) + sinx = csc x

2) cosx^2/sinx + sinx = csc x

3) multiply sinx by (sinx/sinx) to get same denominator

this gives you cosx^2/sinx + sinx^2/sinx = cscx

(cosx^2 + sinx^2)/sinx = cscx

5) rewrite numerator

1/sinx= csc x

and there you go it is proven (you have to know your trig identity to do this so look them up if you don't know them)

• Pre-Calc/Math -

Thank You! :D

• Pre-Calc/Math -

no problem lol this one almost had me stump for alittle

• Pre-Calc/Math -

Ohh it was hard me :/ .Do you think you can answer my other questions?

## Similar Questions

1. ### trig

express this in sinx (1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?
2. ### drwls

My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to …
3. ### precalc

verify the identity ((cosxcotx)/(1-sinx))-1=cscx
4. ### Pre-Calculus

Find a numerical value of one trigonometric function of x if tanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1 d)sinx=1/2
5. ### pre calc

prove identity cscx-(cosx)(cotx)=sinx
6. ### Trig Help

Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)] =[sinx+sin^2x]/[sinx+1] =[sinx+(1-cos^2x)]/[sinx+1] =?
7. ### Pre-Cal

How do I do these questions? I'm supposed to prove them so that both sides are the same and I'm only supposed to manipulate one side and leave the other side alone but I'm stuck. Problem 1. (secx/cosx)-(cscx/sinx)=tan^2x-cot^2x Problem
8. ### Math

Im really struggling with these proving identities problems can somebody please show me how to do these?
9. ### Math

I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equation Problem 1. sinx + cosx + sinx + tanx + cosxcotx = secx + cscx Problem 2. ((sinx + cosx)/(1 + tanx))^2 + ((sinx - cos^2x)/(1 …
10. ### Precalculus/Trig

I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1-cosx Simplified: cosx + sin^3x/sin^3x = cscx/1-cosx I don't know …

More Similar Questions