Chemistry

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50.0mL of 0.01M Ba(OH)2 is added to 150.0mL of 0.01M HNO3. What is the new pH of the solution?

  • Chemistry -

    50 mL x 0.01M Ba(OH)2 = 0.5 millimoles.
    150 mL x 0.01 M HNO3 = 1.5 mmols.
    ....Ba(OH)2 + 2HNO3 ==> Ba(NO3)2 + 2H2O
    I...0..........1.50........0.........0
    added 0.5...............................
    C....-0.5......-1.00......0.5........
    E.......0.......0.5.........0.5........
    (HNO3) = 0.5 millimols/200 mL = 0.0025 M
    I work in millimoles when there are so many zeros. For example, for the Ba(OH)2 part.
    mols = M x L = 0.01 x 0.050 = 0.0005 mol.
    But millimols = 50 x 0.01 = 0.500.
    You can change to mols in the above if you wish by dividing millimoles by 1000.

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