posted by zarmeen .
The combustion of propane is given by the following reaction:
C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (g)
If 5.00 L of propane are burned in in the presence of excess O2, how many liters of carbon dioxide will be formed?
5.00L propane x (3 mols CO2/1 mol C3H8) = 5.00 x 3/1 = ?