posted by Billy
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=-16t^2+vt+s(where h and s are in ft, t is in seconds and v is in ft/sec)
a ball is thrown upward with initial velocity of 96 ft/sec from the top of a 100 ft. bridge. Determine the time that it takes for the ball to get to a height of 200 ft.
Round your answers to 2 decimals, separated by a comma.
Plug the given values into the given Eq and solve for t.