Complete each ionic equation
Cu+2 + SO4-2 + 4H2O ---->
Ca+2 +2NO3-1 + 4H2O ---->
3K+1 +PO4-3 + 6H2O ---->
Na+1 + Br-1 + 2H2O ---->
2Na+1 + S-2 + 2H2O ----->
2NH4+1 + CO3-3 + H2O ---->
2Na+1 + Cr-2 + 2H2O ----->
Mg+2 + 2Br-1 + 4H2O ----->
Na+1 + Cl-1 + 2H2O ------>
To complete each ionic equation, we need to identify the ions and write their respective charges. Then, we can balance the equation by ensuring that the total charges on each side of the arrow are equal.
Let's start with the first equation:
Cu+2 + SO4-2 + 4H2O →
The ions involved are Cu+2, SO4-2, H+, and OH-.
The balanced ionic equation is:
Cu+2 + SO4-2 + 4H2O → Cu(OH)2 + 2H+ + SO4-2
Now, let's move on to the next equation:
Ca+2 + 2NO3-1 + 4H2O →
The ions involved are Ca+2, NO3-1, H+, and OH-.
The balanced ionic equation is:
Ca+2 + 2NO3-1 + 4H2O → Ca(OH)2 + 2H+ + 2NO3-
Continuing with the next equation:
3K+1 + PO4-3 + 6H2O →
The ions involved are K+1, PO4-3, H+, and OH-.
The balanced ionic equation is:
3K+1 + PO4-3 + 6H2O → 3KOH + H3PO4
Moving on to the next equation:
Na+1 + Br-1 + 2H2O →
The ions involved are Na+1, Br-1, H+, and OH-.
The balanced ionic equation is:
Na+1 + Br-1 + 2H2O → NaOH + HBr
Continuing with the next equation:
2Na+1 + S-2 + 2H2O →
The ions involved are Na+1, S-2, H+, and OH-.
The balanced ionic equation is:
2Na+1 + S-2 + 2H2O → Na2S + 2H+ + 2OH-
Moving on to the next equation:
2NH4+1 + CO3-3 + H2O →
The ions involved are NH4+1, CO3-3, H+, and OH-.
The balanced ionic equation is:
2NH4+1 + CO3-3 + H2O → (NH4)2CO3 + 2H+ + OH-
Continuing with the next equation:
2Na+1 + Cr-2 + 2H2O →
The ions involved are Na+1, Cr-2, H+, and OH-.
The balanced ionic equation is:
2Na+1 + Cr-2 + 2H2O → Na2CrO4 + 2H+ + 2OH-
Moving on to the last equation:
Mg+2 + 2Br-1 + 4H2O →
The ions involved are Mg+2, Br-1, H+, and OH-.
The balanced ionic equation is:
Mg+2 + 2Br-1 + 4H2O → Mg(OH)2 + 2H+ + 2Br-
Finally, let's complete the last equation:
Na+1 + Cl-1 + 2H2O →
The ions involved are Na+1, Cl-1, H+, and OH-.
The balanced ionic equation is:
Na+1 + Cl-1 + 2H2O → NaOH + HCl
To complete each ionic equation, we need to identify the ions present in each reactant and product and balance the equation by ensuring that the total charge and number of atoms are equal on both sides of the equation.
1. Cu+2 + SO4-2 + 4H2O ----> Cu(OH)2 + H2SO4
Explanation:
- Cu+2: Copper ion with a charge of +2.
- SO4-2: Sulfate ion with a charge of -2.
- 4H2O: Four water molecules acting as solvent.
- Cu(OH)2: Cupric hydroxide.
- H2SO4: Sulfuric acid.
- The equation is balanced by writing Cu(OH)2 and H2SO4 as the products.
2. Ca+2 + 2NO3-1 + 4H2O ----> Ca(OH)2 + 2HNO3
Explanation:
- Ca+2: Calcium ion with a charge of +2.
- 2NO3-1: Two nitrate ions with a charge of -1 each.
- 4H2O: Four water molecules acting as a solvent.
- Ca(OH)2: Calcium hydroxide.
- 2HNO3: Two molecules of nitric acid.
- The equation is balanced by writing Ca(OH)2 and 2HNO3 as the products.
3. 3K+1 + PO4-3 + 6H2O ----> 3KOH + H3PO4
Explanation:
- 3K+1: Three potassium ions with a charge of +1 each.
- PO4-3: Phosphate ion with a charge of -3.
- 6H2O: Six water molecules acting as a solvent.
- 3KOH: Three molecules of potassium hydroxide.
- H3PO4: Phosphoric acid.
- The equation is balanced by writing 3KOH and H3PO4 as the products.
4. Na+1 + Br-1 + 2H2O ----> NaOH + HBr
Explanation:
- Na+1: Sodium ion with a charge of +1.
- Br-1: Bromide ion with a charge of -1.
- 2H2O: Two water molecules acting as a solvent.
- NaOH: Sodium hydroxide.
- HBr: Hydrobromic acid.
- The equation is balanced by writing NaOH and HBr as the products.
5. 2Na+1 + S-2 + 2H2O ----> 2NaOH + H2S
Explanation:
- 2Na+1: Two sodium ions with a charge of +1 each.
- S-2: Sulfide ion with a charge of -2.
- 2H2O: Two water molecules acting as a solvent.
- 2NaOH: Two molecules of sodium hydroxide.
- H2S: Hydrogen sulfide.
- The equation is balanced by writing 2NaOH and H2S as the products.
6. 2NH4+1 + CO3-3 + H2O ----> (NH4)2CO3 + H3O+
Explanation:
- 2NH4+1: Two ammonium ions with a charge of +1 each.
- CO3-3: Carbonate ion with a charge of -3.
- H2O: One water molecule acting as a solvent.
- (NH4)2CO3: Ammonium carbonate.
- H3O+: Hydronium ion.
- The equation is balanced by writing (NH4)2CO3 and H3O+ as the products.
7. 2Na+1 + Cr-2 + 2H2O ----> 2NaOH + Cr(OH)2
Explanation:
- 2Na+1: Two sodium ions with a charge of +1 each.
- Cr-2: Chromium ion with a charge of -2.
- 2H2O: Two water molecules acting as a solvent.
- 2NaOH: Two molecules of sodium hydroxide.
- Cr(OH)2: Chromium hydroxide.
- The equation is balanced by writing 2NaOH and Cr(OH)2 as the products.
8. Mg+2 + 2Br-1 + 4H2O ----> Mg(OH)2 + 2HBr
Explanation:
- Mg+2: Magnesium ion with a charge of +2.
- 2Br-1: Two bromide ions with a charge of -1 each.
- 4H2O: Four water molecules acting as a solvent.
- Mg(OH)2: Magnesium hydroxide.
- 2HBr: Two molecules of hydrobromic acid.
- The equation is balanced by writing Mg(OH)2 and 2HBr as the products.
9. Na+1 + Cl-1 + 2H2O ----> NaOH + HCl
Explanation:
- Na+1: Sodium ion with a charge of +1.
- Cl-1: Chloride ion with a charge of -1.
- 2H2O: Two water molecules acting as a solvent.
- NaOH: Sodium hydroxide.
- HCl: Hydrochloric acid.
- The equation is balanced by writing NaOH and HCl as the products.