consider the reaction between copper metal and chlorine gas producing solid copper(1) chloride. when 16.2g of copper is reacted in an excess of chlorine, how many grams of copper(1) chloride will be produced

Here is a worked example of a stoichiometry problem. Just follow the steps.

http://www.jiskha.com/science/chemistry/stoichiometry.html

12.6g

To find the grams of copper(1) chloride produced in the reaction between copper metal and chlorine gas, we need to use stoichiometry and the balanced chemical equation.

First, let's write the balanced chemical equation for this reaction:
Cu + Cl2 -> CuCl

According to the equation, one mole of copper reacts with one mole of chlorine gas to form one mole of copper(1) chloride.

Next, we need to calculate the number of moles of copper used in the reaction. We can use the molar mass of copper to convert grams to moles:
Molar mass of copper (Cu) = 63.55 g/mol

moles of copper = 16.2 g / (63.55 g/mol) ≈ 0.255 mol

Since the reaction is 1:1, the number of moles of copper(1) chloride produced will also be 0.255 mol.

Finally, we can calculate the mass of copper(1) chloride by multiplying the number of moles by its molar mass:
Molar mass of copper(1) chloride (CuCl) = 98.999 g/mol

grams of copper(1) chloride = 0.255 mol * 98.999 g/mol ≈ 25.32 g

Therefore, approximately 25.32 grams of copper(1) chloride will be produced.