If a (Delta symbol)b means
(10+a)-(8-b) express 4(delta symbol)5 in simplest form.
What's the problem? Just plug in the values.
a∆b = (10+a)-(8-b)
4∆5 = (10+4)-(8-5) = 14-3 = 11
(10+a)-(8-b) express 4(delta symbol)5 in simplest form.
a∆b = (10+a)-(8-b)
4∆5 = (10+4)-(8-5) = 14-3 = 11