algebra 2

posted by Jess

Carlos wants to make a scale drawing of a rectangle. he wants the rectangle to have a length of (x-1) units and an area of 1-x/x^2+1 square units. What can you say about how wide the rectangle should be? Explain.

  1. Reiny

    I will assume you want the area to be
    (1-x)/(x^2 +1)

    area = l x w
    so (1-x)/(x^2 + 1 ) = w(x-1)
    w = [ (1-x)/(x^2 + 1) ] / (x-1)
    = -1/(x^2 + 1)

    What I would say is "There is no real number for the width"

    -since x^2 is always positive, then x^2 + 1 is always positive
    Thus -1/(a positive) = a negative
    We cannot have a negative width

    unless you want your typed version to have a different meaning besides my interpretation.
    the way you typed it it would have a value of 2 - 1/x
    and I am pretty sure you didn't mean that.

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