ALGEBRA
posted by Randy .
Consider the following expression.
\(x + 2 y  2 z\)  (x  2 y + 2 z)
(a) Simplify the expression.

4y4z

first off, I like to circle to common ones... so I first circle the two x's. Since we are subtracting, it would be xx which is 0. Thenm i circled the 2y's. It would be
2y  (2Y) aka 2y +2y which is 4y. Then, 2z2z which is 4z.
it would be 0+4y4z and you obviously do not need the zero so the guy up there, visoth is right.
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