# physics

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A 34 g glass thermometer reads 21.6°C before it is placed in 135 mL of water. When the water and thermometer come to equilibrium, the thermometer reads 38.7°C. What was the original temperature of the water?

Physics - bobpursley, Tuesday, April 24, 2012 at 5:53pm

the sum of heats gained is zero.

massglass*specheatglass*(21.6-38.7)+135*specheatwater*(Ti-38.6)=0

solve for Ti

Physics - Akbar, Tuesday, April 24, 2012 at 6:58pm

• physics -

well, it is wrong, you know the final answer is between 21.6 and 38.7C

Let me see your calculations, including what you used as specific heats of glass and water.

• physics -

This is how I did it:

(.034)(840)(21.6-38.7)+135(4186)(Ti-38.6)

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