When 6200g of ethylene glycol and 16600g terephtalic acid reacted completely to generate poly(ethyleneterephtalate)(PET),how many grams of H20 generated?
My working:
mol of ethylene glycol = 6200g/(62g/mol)
= 100 moles
mol terephtalic acid = 16600g/(166g/mol)
= 100 moles
So,both have equal moles
Reactions between these two monomers yield 100 moles of PET and 200 moles of H20.
So,the mass of H2O generated is :
200(H2O) = 200 X 18 = 3600g
Is my solution correct? Could Dr.Bob please recheck my steps? Thank you