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How many moles of ions are contained in 1.4 L of a 1.6 M solution of Mg(NO3)2?

  • chemistry -

    mols Mg(NO3)2 = M x L = ?
    mols Mg = same as mols Mg(NO3)2.
    moles NO3^- = 2x mols Mg(NO3)2
    total mol = mols Mg^2+ + mols NO3^-

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