how many grams of magnesium carbonate are in a sample that has 1.58 x 10^24 oxygen atoms?
how many sulfur atoms are in 2.57 g of iron (III) sulfate?
MgCO3.
mols O atoms = 1.58E24/6.02E23 = ?
mols MgCO3 = 1/3 of that.
g MgCO3 = mols MgCO3 x molar mass MgCO3.
mols Fe2(SO4)3 = grams/molar mass = ?
mols S atoms is 3x that.
1 mol S atoms will contain 6.02E23 atoms; therefore, 3 mols will be >>>>>>.
73.7g
1.16 x 10^22 sulfur atoms
To determine the number of grams of magnesium carbonate in a sample, we need to use the mole concept and the molar mass of magnesium carbonate. Here are the steps to calculate it:
Step 1: Find the molar mass of magnesium carbonate (MgCO3):
The molar mass is calculated by adding up the atomic masses of each element in the compound.
- Atomic mass of Mg: 24.31 g/mol
- Atomic mass of C: 12.01 g/mol
- Atomic mass of O: 16.00 g/mol
Now, sum up the atomic masses:
Molar mass of MgCO3 = (1 × Mg) + (1 × C) + (3 × O)
Molar mass of MgCO3 = (1 × 24.31) + (1 × 12.01) + (3 × 16.00)
Molar mass of MgCO3 ≈ 84.31 g/mol
Step 2: Calculate the number of moles of oxygen atoms:
We are given the number of oxygen atoms in the sample (1.58 x 10^24 atoms). To convert this into moles, we need to divide by Avogadro's number (6.022 x 10^23 atoms/mol):
Number of moles of oxygen atoms = (1.58 x 10^24 atoms) / (6.022 x 10^23 atoms/mol)
Number of moles of oxygen atoms ≈ 2.62 moles
Step 3: Use the stoichiometry of the compound:
From the balanced chemical equation of magnesium carbonate (MgCO3), we can see that there is one oxygen atom for every magnesium carbonate molecule:
MgCO3 → 1 Mg + 1 C + 3 O
Step 4: Calculate the number of moles of magnesium carbonate:
Since there is a 1:1 ratio between the moles of oxygen atoms and the moles of magnesium carbonate:
Number of moles of magnesium carbonate = 2.62 moles
Step 5: Convert moles to grams:
Finally, to convert the number of moles of magnesium carbonate to grams, we multiply the number of moles by the molar mass:
Mass (grams) of magnesium carbonate = 2.62 moles × (84.31 g/mol)
Mass (grams) of magnesium carbonate ≈ 219.91 grams
Therefore, there are approximately 219.91 grams of magnesium carbonate in the given sample.