chemistry

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how many grams of magnesium carbonate are in a sample that has 1.58 x 10^24 oxygen atoms?

  • chemistry -

    how many sulfur atoms are in 2.57 g of iron (III) sulfate?

  • chemistry -

    MgCO3.
    mols O atoms = 1.58E24/6.02E23 = ?
    mols MgCO3 = 1/3 of that.
    g MgCO3 = mols MgCO3 x molar mass MgCO3.

  • chemistry -

    mols Fe2(SO4)3 = grams/molar mass = ?
    mols S atoms is 3x that.
    1 mol S atoms will contain 6.02E23 atoms; therefore, 3 mols will be >>>>>>.

  • chemistry -

    73.7g

  • chemistry -

    1.16 x 10^22 sulfur atoms

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