What is the compound name for Sb2(CrO4)5?
This is the only question I am having trouble with.
To determine the compound name for Sb2(CrO4)5, we need to follow a few steps:
Step 1: Identify the symbols for each element in the compound.
- Sb represents the element antimony.
- Cr represents the element chromium.
- O represents the element oxygen.
Step 2: Determine the charge of each element based on the subscript or oxidation number in the compound.
- The subscript 2 after Sb indicates that antimony has a charge of +3. This means each antimony ion (Sb) has a +3 charge.
- The subscript 5 after (CrO4) indicates that there are five (CrO4) groups in the compound.
Each (CrO4) group, called a chromate ion, has a charge of -2. So, the total charge of five (CrO4) groups is -10.
Step 3: Determine the overall charge of the compound.
- The compound Sb2(CrO4)5 has two antimony ions, each with a charge of +3, and five chromate ions, each with a charge of -2.
- Since there are two antimony ions with a total charge of +6 and five chromate ions with a total charge of -10, the overall charge of the compound is equal to -4.
Step 4: Use the charges of each element to balance the compound name.
- In this case, since the compound has a negative overall charge, the name will end in "-ate."
- The prefix "di-" is used for the subscript 2 in Sb2.
- The prefix "penta-" is used for the subscript 5 in (CrO4)5.
Putting all the naming components together, the compound name for Sb2(CrO4)5 is diantimony pentachromate.
So, the compound name is diantimony pentachromate.
To determine the compound name for Sb2(CrO4)5, you'll need to follow a few steps. Here's how you can do it:
1. Identify the formula components:
- The symbol "Sb" stands for antimony.
- The symbol "CrO4" represents chromium (VI) oxide or chromate ion.
2. Determine the charge of each component:
- Antimony (Sb) has a fixed charge of +3.
- Chromium (Cr) has a variable charge, which we can deduce from the formula of the compound. Since there are five chromate ions (CrO4) and the overall charge of the compound is 0, the charge of chromium can be calculated by dividing the total charge by the number of chromate ions: (0 / 5 = 0). Therefore, chromium has a charge of +6.
3. Use the charges to balance the compound:
- Since Sb has a charge of +3 and Cr has a charge of +6, we need two antimony atoms to balance the charge of one chromium atom: Sb2Cr.
- For the chromate ion, we have five of them in the compound, so the formula becomes Sb2(CrO4)5.
4. Write the compound name:
- The compound Sb2(CrO4)5 can be named as Antimony(III) Chromate.
Therefore, the compound name for Sb2(CrO4)5 is Antimony(III) Chromate.