How many grams of sodium-hydroxide will react with 49g of phosphoric acid?
H3PO4=98g/mol,NaOH=40/mol.The equation is:3H2O+Na3PO4
49 g H3PO4 = ? mols. mols = grams/molar mass
Use the coefficients to convert mols H3PO4 to mols NaOH.
Then g NaOH = mols x molar mass.
To determine the number of grams of sodium hydroxide that will react with 49g of phosphoric acid, we first need to determine the molar mass of phosphoric acid (H3PO4) and sodium hydroxide (NaOH).
The molar mass of phosphoric acid (H3PO4) is given as 98g/mol, and the molar mass of sodium hydroxide (NaOH) is 40g/mol.
Next, we need to find the molar ratio between the two compounds based on the balanced equation:
3H2O + Na3PO4
From this equation, we see that one mole of phosphoric acid reacts with three moles of sodium hydroxide.
To find the number of moles of phosphoric acid (H3PO4) in 49g, we divide the given mass by the molar mass:
Number of moles of phosphoric acid = Mass of phosphoric acid / Molar mass of phosphoric acid
= 49g / 98g/mol
= 0.5 mol
Since the molar ratio between phosphoric acid and sodium hydroxide is 1:3, we can conclude that 0.5 moles of phosphoric acid will react with 1.5 moles of sodium hydroxide.
Finally, to find the mass of sodium hydroxide (NaOH), we multiply the number of moles by the molar mass:
Mass of sodium hydroxide = Number of moles of sodium hydroxide * Molar mass of sodium hydroxide
= 1.5 mol * 40g/mol
= 60g
Therefore, 60g of sodium hydroxide will react with 49g of phosphoric acid.