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Determine whether the triangle has no/one/two solutions. Then Find and round measures of sides to the nearest tenth and measures of the angles to the nearest degree.

A= 50 degrees, a=34, b=40

  • Math -

    Given: A = 50 Deg., a = 34, b = 40.

    sinB/b = sinA/a.
    sinB/40 = sin50/34.
    sinB = 40(sin50/34) = 0.9012.
    B = 64 Deg.

    C = 180 - A - B = 180 - 50 - 64=66 Deg.

    c/sinC = a/sinA.
    c/sin64 = 40/sin50.
    c = sin64(40/sin50) = 46.9.

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