calculus

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Suppose x=4sin(theta, for theta (-pie/2, pie/2). Rewrite(sqrt16-x^2)^3/x^3

(Sorry Im not very good at making symbols. I hope you know what I mean here! if not I can try to rewrite it a different way)

• calculus -

malachi has three tvs of: 25",27",32".
what the average size of malachi tvs?

• calculus -

x = 4sinθ

sinθ = x/4
so, the other side is √(16-x^2)

√(16-x^2)/x = cotθ

[√(16-x^2)/x]^3 = cot^3(θ)

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