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An athlete executing a long jump leaves the ground at a 28.0 angle and lands 7.60m away.
part a)What was the takeoff speed?

part b) If this speed were increased by just 8.0 % , how much longer would the jump be?

i got for part a)9.48 m/s
but i need help with part b

  • physics -

    L = v^2•sin2α/g ,
    v = sqrt(L•g/sin2α) = 9.48 m/s.
    New velocity
    V =1.08•v = 1.08•9.48= 10.24 m/sþ
    New range is L1 = V^2•sin2α/g = 8.87 m.
    ΔL = 8.87 – 7.6 = 1.27 m

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