Physics
posted by ####Nadine#### .
A 2.11 cm high insect is 1.31 m from a 125 mm focallength lens. Where is the image?
Distance of the image is ?
How high is it?
What type is it?

Physics 
Elena
Find the image distance from
1/do + 1/di = 1/f,
1/1.31 + 1/di = 1/(125•10^3).
di =  … (m) – virtual, in front of the length
The height of the image may be found from
M =h1/h2 =  di/do,
h1 =  … (inverted) 
Physics 
####Nadine####
Thank you Elena, I had virtual and inverted also, but the book says it is virtual and upright. so I thought everything else was worry. Maybe it is the book?

Physics 
Elena
Anybody's guess...
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