Can't figure this out, HELP!:

What is the velocity (v) of a stream with a discharge (Q) of 8.53 x 10^3 m 3/s and a cross-sectional area (A) of 5.27 x 10^3 m2?

To find the velocity (v) of the stream, you would use the formula v = Q/A, where Q is the discharge and A is the cross-sectional area.

In this case, the given discharge Q is 8.53 x 10^3 m^3/s, and the given cross-sectional area A is 5.27 x 10^3 m^2.

To find the velocity (v), simply divide the discharge by the cross-sectional area using the given formula:

v = Q / A

Plugging in the given values:

v = (8.53 x 10^3 m^3/s) / (5.27 x 10^3 m^2)

Now, simplify the equation by dividing the numbers:

v = 1.62 m/s

Therefore, the velocity (v) of the stream is 1.62 m/s.