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A physics student drops a physics text book into a mine shaft 250m deep,where the average mine temperature is 5degrees celsius.Show that the sound of the book striking the bottom is heard after 7.82seconds

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    d = Vo*t + 4.9*t^2 = 250 m.
    0 + 4.9t^2 = 250.
    t^2 = 250 / 4.9 = 51.0.
    Tf = 7.14 s. = Fall time.

    d = V*T.
    T = d/V = 250m / 343m/s = 0.729 s. =
    Time for sound to travel 250 meters up.

    Tf + T = 7.14 + 0.729 = 7.87 s.

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