Calculus AB
posted by janki .
y=6x y=x^2
Find the area of the region by
integrating with respect to x.
Find the area of the region by integrating with respect to y.

i got the intersection pts to be(3,9)and (2,4)....i then took the integral and found the answer to be 20.8333 for both parts...HOWEVER...its wrong! please help!

Your intersection points are correct
Method1:
the effective height of a slice = 6x  x^2
area = ∫ (6x  x^2) dx from x = 3 to 2
= [6x  x^2/2  x^3/3] from 3 to 2
= 12  2  8/3  (18 9/2  (27/3) )
= 10  8/3 + 9 + 9/2
= 19 + 11/6
= 20 5/6 or 125/6 , so you were right
Respond to this Question
Similar Questions

mathematics
find the area of the region between the curve y = 3x^2 and the line y = 1 by integrating with respect to y you first have to solve for x x=(3y)^(1/2) then area ⌠ (3y)^(1/2 dy from 1 to 3 ⌡ =2/3 (3y)^(3/2  from 1 … 
Calc
y = x^2 y = 6  x Find the area of the region by integrating (a) with respect to x and (b) with respect to y. 
Calc
y = x^2 y = 6  x Find the area of the region by integrating (a) with respect to x and (b) with respect to y. 
calculus
set up sums of integrals that can be used to find the area of the region bounded by the graphs of the equations by integrating with respect to y y=square root of x; y= x, x=1, x=4 
calculus
the region enclosed by 2y=5xy=5 and 2y+3x=8. Decide whether to integrate with respect to x or y, and then find the area of the region. The area is 
calculus1
Set up the integrals that can be used to find the area of the region by integrating with respect to X and Y (the region is bounded by y=3x,y=x,y=4x) Anyone help me set up the integrals? 
calc
Find the area of the region bounded by the curves y equals the inverse sine of x divided by 4, y = 0, and x = 4 obtained by integrating with respect to y. Your work must include the definite integral and the antiderivative. 
calculus review please help!
1) Find the area of the region bounded by the curves y=arcsin (x/4), y = 0, and x = 4 obtained by integrating with respect to y. Your work must include the definite integral and the antiderivative. 2)Set up, but do not evaluate, the … 
Calculus  Integrals
Consider the region enclosed by the graphs of x=y^25 and x=3y^2 a)Express the area of this region by setting up an integral with respect to x b) Express the area of this region by setting up an integral with respect to y c) Find … 
Calculus
Find the area of the region bounded by the curves of y=sin^1(x/4), y=0, and x=4 obtained by integrating with respect to y. Your work must include the definite integral and the antiderivative. I am really confused on this question. …