Physics

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Steel railroad tracks of length L = 18.30 m are laid at 10.0° C. How much space should be left between the track sections if they are to just touch when the temperature is T = 49.0° C? mm

Please help. I have tried this
L° α Δt = 18.3 * 13 10^-6 * (49 -10) = .92781cm which equals to 9.2681 mm I think but its wrong. please help.

  • Physics -

    I have 12 * 10^-6 for the thermal expansion coef of steel
    meters in --> meters out
    18.3 * 12 * 10^-6 * (39) = 8564*10^-6 m
    = .008564 m = 8.564 mm

  • Physics -

    Thank you so much Damon :)!

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