# Algebra

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I am not understanding these kinds of problems: I cannot simplify with understanding.

7 times the 4th root of m^3 plus 9 times the 4th root of 256m^3.

• Algebra -

it can also be written as:
7 x [m^(3/4)] + 9[256m^(3/4)]

solve it

• Algebra -

a correction is in order, as it should be

7 x [m^(3/4)] + 9[(256m^3)^(1/4)]

= 7∜m^3 + 9(∜256∜m^3)
= 7∜m^3 + 9(4∜m^3)
= 43∜m^3

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