1 + 1/4 + (1.3)/(4.8) + (1.3.5)/(4.8.12)+...... = _____

Expand (1-x/2)^(-1/2) using Maclaurin Series and set x=1 and see what happens.

m not getting the answer by dat way.....plz help

If you have done MacLaurin expansion, you should be able to expand the expression.

What answer did you get?

1/2^(1/2)

i got the same answer too

Oh, sorry, the expression I gave is not correct.

It should have read:
[1/(1-x/2)]^(-1/2)
which should expand to
1+1/4+1.3/(4.8)+1.3.5/(4.8.12)+...

Please disregard the previous correction.

The original expression IS correct, as it says:
(1-x/2)^(-1/2) [note the negative sign of the exponent]
=sqrt[1/(1-x/2)]
and should expand to:
1+1/4+1.3/(4.8)+1.3.5/(4.8.12)+...

so watz d method?

and note that (1-x/2) means (1-(x/2)) by the priority of multiplication over addition.

thanx