Determine the mass of 7.79 ×1023 atoms Cl.
Answer in units of g
To determine the mass of 7.79 × 10^23 atoms of chlorine (Cl), we need to use the concept of molar mass.
The molar mass of an element represents the mass of one mole of that element in grams.
Find the molar mass of chlorine (Cl):
- The atomic mass of chlorine is approximately 35.45 g/mol.
Now, we can use this value to calculate the mass of 7.79 × 10^23 atoms of Cl:
1. Calculate the moles of Cl:
- Moles = Number of atoms / Avogadro's number
- Moles = 7.79 × 10^23 atoms / 6.022 × 10^23 atoms/mol
- Moles ≈ 1.29
2. Calculate the mass of Cl:
- Mass = Moles × Molar mass
- Mass ≈ 1.29 mol × 35.45 g/mol
- Mass ≈ 45.75 g
Therefore, the mass of 7.79 × 10^23 atoms of Cl is approximately 45.75 grams.
To determine the mass of 7.79 × 10^23 atoms of the element chlorine (Cl), we need to use the molar mass of chlorine.
First, we locate the molar mass of chlorine on the periodic table, which is approximately 35.45 g/mol. This means that one mole of chlorine weighs 35.45 grams.
Next, we need to convert the given number of atoms (7.79 × 10^23) to moles. Since 1 mole contains Avogadro's number (6.022 × 10^23) of atoms, we divide the given number of atoms by Avogadro's number:
7.79 × 10^23 atoms Cl / (6.022 × 10^23 atoms/mol) ≈ 1.29 moles of Cl
Now that we have 1.29 moles of Cl, we can calculate the mass in grams by multiplying it by the molar mass of chlorine:
1.29 moles × 35.45 g/mol ≈ 45.76 g
Therefore, the mass of 7.79 × 10^23 atoms of chlorine is approximately 45.76 grams.
mol = 7.79E23/6.022E23 = ?
grams = mols x 35.453 = ?