posted by Hannah
Calculate the pH of an aqueous solution of 0.15 M potassium carbonate.
I know that pH = -log(H30+) but I am not sure how to start this problem.
Chemistry(Please help) - DrBob222, Saturday, April 14, 2012 at 11:09pm
Hydrolyze the CO3^2-.
CO3^- + HOH ==> HCO3^- + OH^-
Do an ICE chart, Kb = Kw/k2 for H2CO3.
so for kb I do 1e-14/.15?
Chemistry(Please help) - DrBob222, Tuesday, April 17, 2012 at 3:27pm
No. Kb = 1E-14/k2 for H2CO3.
How do I set up an ice table when I only have .15M?