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a 7 foot tall man is standing 65 feet away from a tower. if the angle of elevation is 35 degrees. what is the height of the tower to nearest tenth of a foot?

  • trig -

    If there are h feet of tower above the man's eyes, h/65 = tan35°

    so, the tower height is 7 + 65tan35° = 52.5 ft

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