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A flywheel accelerates from rest to an angular velocity of 10.44rad/s at an angular acceleration of 51.57rad/s^2. The diameter of the flywheel is 1.16m.

At this instant, calculate the resultant linear acceleration, in m/s^2, of a point on the circumference of the flywheel.

  • Physics -

    ω = 10.44rad/s ,
    ε = 51.57rad/s^2
    R =D/2.
    Normal (centripetal) acceleration
    a(n) = ω^2•R.
    Tangential acceleration
    a(τ) = ε•R.
    Resultant linear acceleration
    a =sqrt(a(n)^2 + a(τ)^2).

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