Analytical Chem

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Describe the preparation of 100 mL 0.50 M solution of Fe(NO3)3 from a stock solutiion that is 60%(w/w)Fe(NO3)3 solution with a specific gravity of 1.110 g/ml. Calculate the molar NO3 concentration in the resulting solution. Molar Mass of Fe(NO3)3: 241.86

  • Analytical Chem -

    First I would calculate the molarity of the iron(III) nitrate solution.
    1.110 g/mL x 1000 mL x 0.60 = g/L
    Then g/molar mass = mols and this is the M of the soln.
    Then dilute that stock soln using the dilution formula.
    c1v1 = c2v2 where
    c = concn
    v = volume.

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