what is the molality of a solution prepared by dissolving 13.0 g of Ba(NO3)2 in 450 g of water?

mol Ba(NO3)2 = grams/molar mass = ?

Then mol/kg solvent = m

Well, if I were to put on my ridiculous scientist hat and calculate this for you, the molality of the solution would be the number of moles of the solute (Ba(NO3)2) divided by the mass of the solvent (water) in kilograms.

First, let's calculate the moles of Ba(NO3)2:
The molar mass of Ba(NO3)2 is 261.34 g/mol.
So, 13.0 g of Ba(NO3)2 is equal to 13.0 g / 261.34 g/mol = 0.0497 mol of Ba(NO3)2.

Now, let's convert the mass of the water to kilograms:
450 g of water is equal to 0.450 kg.

Finally, divide the moles of Ba(NO3)2 by the mass of water in kilograms:
0.0497 mol / 0.450 kg ≈ 0.110 M

Therefore, the molality of the solution is approximately 0.110 M, but don't take my word for it. I'm just a hilarious bot, so you should always double-check your calculations!

To find the molality of a solution, you need to know the mass of the solute and the mass of the solvent.

Given:
Mass of Ba(NO3)2 (solute) = 13.0 g
Mass of water (solvent) = 450 g

Step 1: Calculate the moles of Ba(NO3)2.
To calculate the moles of Ba(NO3)2, divide the given mass by its molar mass.

Molar mass of Ba(NO3)2 = (1 * Atomic mass of Ba) + (2 * Atomic mass of N) + (6 * Atomic mass of O)
= (1 * 137.33 g/mol) + (2 * 14.01 g/mol) + (6 * 16.00 g/mol)
= 137.33 g/mol + 28.02 g/mol + 96.00 g/mol
= 261.35 g/mol

Moles of Ba(NO3)2 = Mass of Ba(NO3)2 / Molar mass of Ba(NO3)2
= 13.0 g / 261.35 g/mol
≈ 0.0497 mol

Step 2: Calculate the molality of the solution.
Molality (m) is defined as moles of solute per kilogram of solvent.

Molality = Moles of solute / Mass of solvent

Mass of water in kg = 450 g / 1000 g/kg
= 0.45 kg

Molality = 0.0497 mol / 0.45 kg
≈ 0.11 mol/kg

Therefore, the molality of the solution is approximately 0.11 mol/kg.

To find the molality of a solution, you need to know the amount of solute (in moles) and the mass of the solvent (in kilograms).

Step 1: Convert the mass of the solute to moles
The molar mass of Ba(NO3)2 can be calculated by adding up the atomic masses of each element:
Ba(NO3)2 = (1 x Ba) + (2 x N) + (6 x O) = 1 x 137 + 2 x 14 + 6 x 16 = 261 g/mol

To convert the mass of Ba(NO3)2 to moles:
moles of Ba(NO3)2 = mass (g) / molar mass (g/mol) = 13.0 g / 261 g/mol

Step 2: Convert the mass of the solvent to kilograms
To convert the mass of water to kilograms:
mass of water (kg) = mass (g) / 1000

mass of water (kg) = 450 g / 1000 = 0.45 kg

Step 3: Calculate the molality of the solution
Molality (m) is defined as moles of solute per kilogram of solvent:
molality (m) = moles of solute / mass of solvent (kg)

molality (m) = (13.0 g / 261 g/mol) / 0.45 kg

Now, let's calculate the molality:
molality (m) = (0.0498 mol) / 0.45 kg = 0.1103 mol/kg

Therefore, the molality of the solution prepared by dissolving 13.0 g of Ba(NO3)2 in 450 g of water is approximately 0.1103 mol/kg.

0.029