college Calculus Help!
posted by LILY
If f(x)= ∫(21,x) t^5 dt then f'(x).
my answer was 1/6 (21^6x^6) it said it's wrong.

Reiny
You must be Mily from below.
same thing as before
∫ t^5 dt from t=21 to t=x
= (1/6)t^6 from t21 to t=x
= (1/6)x^6  (1/6)(21)^6
= (1/6)(x^6  21^6) 
LILY
what about f ' (x)?
i did with (1/6)(x^621^6) but its wrong
f(x)=∫(21,x) t^5
f'(x)= x^5
i font know 
LILY
but thanks

LILY
i got it, it correct answer is f'(x)=x^5.
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