# college Calculus Help!

posted by LILY

If f(x)= ∫(21,x) t^5 dt then f'(x).

my answer was 1/6 (21^6-x^6) it said it's wrong.

1. Reiny

You must be Mily from below.

same thing as before

∫ t^5 dt from t=21 to t=x
= (1/6)t^6 from t-21 to t=x
= (1/6)x^6 - (1/6)(21)^6
= (1/6)(x^6 - 21^6)

2. LILY

i did with (1/6)(x^6-21^6) but its wrong

f(x)=∫(21,x) t^5
f'(x)= x^5
i font know

3. LILY

but thanks

4. LILY

i got it, it correct answer is f'(x)=-x^5.

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