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Chemistry

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The pH of a 0.100 M solution of an aqueous weak acid (HA) is 4.00. What would the Ka for the weak acid be?

  • Chemistry -

    pH = 4.0; (H^+) = 1E-4
    ............HA ==> H^+ + A^-
    initial....0.1......0.....0
    change.....-x........x.....x
    equil....0.1-x.......x.....x
    x = 1E-4
    Ka = (H^+)(A^-)/(HA)
    Substitute from the ICE chart and solve for Ka.

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