ALGEBRA
posted by Randy .
Evaluate the given expressions (to two decimal places).
(a) log((23.0)
((b) log_(2) \(128\)
text((c) ) log_(9) \(1\)

get out your calculator, do the calculations, and post your results for confirmation.
Recall that log_{b}n = ln(n)/ln(b)
Respond to this Question
Similar Questions

ALGEBRA
(a) Write the expression in terms of natural logarithms. (Express all logarithmic functions in terms of ln(x) in your answer.) log_(8.5) \(127\) = Give a calculator approximation (correct to four decimal places). log_(8.5) \(127\) … 
ALGEBRA
Use the definition of logarithm to simplify each expression. (a) )log_(3b) \(3b\) ((b) )log_(8b) \((8b)^6\) (c) )log_(10b) \((10b)^(13)\) 
ALGEBRA
Evaluate the given expressions (to two decimal places). (a) ) log((23.0) (b) ) log_(2) \(128\) (c) ) log_(9) \(1\) 
ALGEBRA
Use the definition of logarithm to simplify each expression. text((a) )log_(3b) \(3b\) text((b) )log_(4b) \((4b)^6\) text((c) )log_(7b) \((7b)^(11)\) 
ALGEBRA
Write the expression in terms of common logarithms, and then give a calculator approximation (correct to four decimal places). log_(7) \(80\) 
ALGEBRA
(a) Write the expression in terms of natural logarithms. (Express all logarithmic functions in terms of ln(x) in your answer.) log_(8.9) \(135\) = (b) Give a calculator approximation (correct to four decimal places). log_(8.9) \(135\) … 
Trigonometry
Every point (x,y) on the curve y = \log_{2}{3x} is transferred to a new point by the following translation (x',y') =(x+m,y+n), where m and n are integers. The set of (x',y') form the curve y = \log_{2}{(12x96)} . What is the value … 
Algebra please can you ck my work
Evaluate the given expressions (to two decimal places). log 1.69 =123 log 2^512 = .09 log 2^1 = 0 log o.o46 =1.34 Thank you 
Algebra
Solve (log base{3} +(log_{3} x)) = 1. x = 
algebra
Let $x$, $y$, and $z$ be positive real numbers that satisfy \[2 \log_x (2y) = 2 \log_{2x} (4z) = \log_{2x^4} (8yz) \neq 0.\] The value of $xy^5 z$ can be expressed in the form $\frac{1}{2^{p/q}}$, where $p$ and $q$ are relatively prime …