# chem 101

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This is second part is built off the first question. These are all from a practice test.

How much heat is required to raise the temperature of exactly one liter of water fro m 60 °F to 180 °F?

How much alcohol must be burned to generate enough heat to warm the water as described in problem 3?

the only mention of an alcohol is ethyl alcohol (C2H6O) in the question before this where you find its heat of combustion.

• chem 101 -

60F is 15.55 C
180 F is 82.22C
delta T = 82.22-15.55 = 66.67
q = mass x specific heat x delta T
q = 100g x 4.184 x 66.67
q = 278,947 = 279 kJ.

Burning alcohol (46 g ethanol) provides 1238.43 kJ/mol. We want to know how many g ethanol to burn to provide 279 kJ.
46 g x (279/1238.43) = 10.36 g which rounds to 10.4 g.

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