calculus antiderivation
posted by lindsay .
Given that the graph of f(x) passes through the point (2,5) and that the slope of its tangent line at (x, f(x))is 3x+5, what is f(3) ?

if dy/dx = 3x+5 , then
y = (3/2)x^2 + 5x + c
when x=2, y = 5
5 = (3/2)(4) + 10 + c
5 = 6 + 10 + c
c = 11
f(x) = (3/2)x^2 + 5x  11
f(3) = (3/2)(9) +15  11 = 35/2
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